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(2)
7x² – x(x+13) = 15
7x² – x² – 13x = 15
6x² – 13x – 15 = 0
(x + 13) = -b/a = 13/6
x13 = c/a = 13/6

(2ai)
x² +13² = (x+13)² – 2×13
= (13/6)² – 2 (-15/6)
= 169/36 + 30/6
= 169+180/36
= 349/36

(2aii)
1/x1 + 1/341
= 3 + 1 + x + 1/(x + 1)(3+1)
= (x + 3) +2/x3+(x+3)+1
= 13+2/6
= -15/6 + 13/6 +1
= 13/6 + 2/1 ÷ -15/6 +13/6 +1
= 13 + 12/6 ÷ 15+13+6/6
= 25/6 ÷ 4/6
= 25/6 x 6/4
= 25/4

Q1a

5/¯2+/¯3
——-
/5/¯2-/¯3

=5/¯2+/¯3
——–
5/¯2-/_3

*5/¯2+3
——-
5/¯2+/¯3

=50+5/¯6+5/¯6+3
————–
50+5/¯6-5/¯6-3

=53+10/¯10+6
———–
47

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